48d^2-90d-12=0

Solution for 48d^2-90d-12=0 equation:

48d^2-90d-12=0

a = 48; b = -90; c = -12;
Δ = b2-4ac
Δ = -902-4·48·(-12)
Δ = 10404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10404}=102$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-90)-102}{2*48}=\frac{-12}{96}
=-1/8
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-90)+102}{2*48}=\frac{192}{96}
=2
$